Given:
TS is tangent to the circle at S, with O as the center.
Angle at O is \(90^\circ\) (radius is perpendicular to tangent).
Angle ∠SOT = 90°, ∠OST = x°, ∠OTS = 3x°
Step 1: Triangle Angle Sum
In triangle OST:
\[\angle SOT + \angle OST + \angle OTS = 180^\circ\]
\[90^\circ + x^\circ + 3x^\circ = 180^\circ\Rightarrow 90^\circ + 4x^\circ = 180^\circ\Rightarrow 4x = 90\Rightarrow x = 22.5^\circ\]
Step 2: Calculate \(2x\)
\[2x = 2 \times 22.5^\circ = 45^\circ\]
Final Answer:
The value of \(2x^\circ\) is 45°.