Question:medium
In common emitter amplifier, a change of \(0.2\) mA in the base current causes a change of \(5\) mA in the collector current. If input resistance is \(2\) k\(\Omega\) and voltage gain is \(75\), the load resistance used in the circuit is
In common emitter amplifier, a change of \(0.2\) mA in the base current causes a change of \(5\) mA in the collector current. If input resistance is \(2\) k\(\Omega\) and voltage gain is \(75\), the load resistance used in the circuit is
Show Hint
Voltage gain = beta x (R_L / R_in), with beta = delta Ic / delta Ib.
Updated On: Oct 1, 2026
- \(2\) k\(\Omega\)
- \(3\) k\(\Omega\)
- \(4\) k\(\Omega\)
- \(6\) k\(\Omega\)
Show Solution
The Correct Option is D
Solution and Explanation
Step 1: Current gain
$\beta = 5/0.2 = 25$.
Step 2: Rearrange
$R_L = A_V R_{in}/\beta$.
Step 3: Value
$R_L = 75 \times 2/25 = 6$ k$\Omega$. Option (D).
Final Answer:
Option (D). \[ \boxed{6\text{ k}\Omega} \]
$\beta = 5/0.2 = 25$.
Step 2: Rearrange
$R_L = A_V R_{in}/\beta$.
Step 3: Value
$R_L = 75 \times 2/25 = 6$ k$\Omega$. Option (D).
Final Answer:
Option (D). \[ \boxed{6\text{ k}\Omega} \]
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