Question

In an isobaric process, 200 J of heat is supplied to a gas. The gas does 50 J of work. What is the change in internal energy?

• A. 150 J
• B. 250 J
• C. 100 J
• D. 200 J

Hint:

In an isobaric process, use the first law of thermodynamics: \( \Delta U = Q - W \) to calculate the change in internal energy.

Answer 1

The Correct Option is A

For an isobaric process, the first law of thermodynamics is expressed as: \[ \Delta U = Q - W, \] where \(Q = 200 \, \text{J}\) denotes the heat added, \(W = 50 \, \text{J}\) signifies the work performed by the gas, and \(\Delta U\) represents the alteration in internal energy. Applying the given values: \[ \Delta U = 200 - 50 = 150 \, \text{J}. \] Consequently, the internal energy change is calculated as: \[ \boxed{150 \, \text{J}}. \]