Question:medium
In an examination, Raman scored 25 marks less than Rohit. Rohit scored 45 more marks than Sonia. Rohan scored 75 marks which is 10 more than Sonia. Ravi's score is 50 less than the maximum marks of the test. What approximate percentage of marks did Ravi score in the examination, if he gets 34 marks more than Raman?
In an examination, Raman scored 25 marks less than Rohit. Rohit scored 45 more marks than Sonia. Rohan scored 75 marks which is 10 more than Sonia. Ravi's score is 50 less than the maximum marks of the test. What approximate percentage of marks did Ravi score in the examination, if he gets 34 marks more than Raman?
Show Hint
Work out each person's marks step by step starting from Sonia's score.
Updated On: Jul 16, 2026
- 90
- 70
- 80
- 60
Show Solution
The Correct Option is B
Solution and Explanation
Step 1: Write every score in terms of Sonia's marks.
Let Sonia's score be $s$. Rohan's fixed score of 75 is given as 10 more than Sonia, so $s = 65$, which checks out independently. Rohit $= s+45$, Raman $= (s+45)-25 = s+20$, and Ravi $= (s+20)+34 = s+54$.
Step 2: Combine into a single expression for the percentage.
Maximum marks $= \text{Ravi's score} + 50 = (s+54)+50 = s+104$. So the required percentage is $\frac{s+54}{s+104} \times 100$.
Final Answer:
Substituting $s=65$: $\frac{119}{169} \times 100 \approx 70\%$, confirming option B. \[ \boxed{70\%} \]
Let Sonia's score be $s$. Rohan's fixed score of 75 is given as 10 more than Sonia, so $s = 65$, which checks out independently. Rohit $= s+45$, Raman $= (s+45)-25 = s+20$, and Ravi $= (s+20)+34 = s+54$.
Step 2: Combine into a single expression for the percentage.
Maximum marks $= \text{Ravi's score} + 50 = (s+54)+50 = s+104$. So the required percentage is $\frac{s+54}{s+104} \times 100$.
Final Answer:
Substituting $s=65$: $\frac{119}{169} \times 100 \approx 70\%$, confirming option B. \[ \boxed{70\%} \]
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