To solve the problem, let us first understand the terms involved when dealing with an equilateral triangle:
- In-radius (r): The radius of the circle inscribed within the triangle.
- Circum-radius (R): The radius of the circle circumscribed around the triangle.
- Ex-radius (re): The radius of the excircle opposite to any side of the triangle.
In an equilateral triangle with side length \(s\), these radii are given by:
- In-radius: \(r = \frac{s \sqrt{3}}{6}\)
- Circum-radius: \(R = \frac{s}{\sqrt{3}}\)
- Ex-radius: \(r_e = \frac{s \sqrt{3}}{2}\)
Next, let’s find the ratios:
- Ratio of the in-radius to the circum-radius:
- \(\frac{r}{R} = \frac{\frac{s \sqrt{3}}{6}}{\frac{s}{\sqrt{3}}} = \frac{1}{2}\)
- Ratio of the circum-radius to the ex-radius:
- \(\frac{R}{r_e} = \frac{\frac{s}{\sqrt{3}}}{\frac{s \sqrt{3}}{2}} = \frac{1}{3}\)
Now, combining these results, the ratio of the in-radius, circum-radius, and one of the ex-radii is:
This matches the given correct answer option: \(1:2:3\).
Therefore, the final answer is:
- In-radius, circum-radius, and one of the ex-radii of an equilateral triangle are in the ratio: \(1:2:3\).