Question:medium

In an equilateral triangle, the in-radius, circum-radius and one of the ex-radii are in the ratio

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For equilateral triangle, \(R = 2r\) and \(r_1 = 3r\).
Updated On: Jun 18, 2026
  • \(2:3:5\)
  • \(1:2:3\)
  • \(1:3:7\)
  • \(3:7:9\)
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The Correct Option is B

Solution and Explanation

To solve the problem, let us first understand the terms involved when dealing with an equilateral triangle:

  1. In-radius (r): The radius of the circle inscribed within the triangle.
  2. Circum-radius (R): The radius of the circle circumscribed around the triangle.
  3. Ex-radius (re): The radius of the excircle opposite to any side of the triangle.

In an equilateral triangle with side length \(s\), these radii are given by:

  • In-radius: \(r = \frac{s \sqrt{3}}{6}\)
  • Circum-radius: \(R = \frac{s}{\sqrt{3}}\)
  • Ex-radius: \(r_e = \frac{s \sqrt{3}}{2}\)

Next, let’s find the ratios:

  1. Ratio of the in-radius to the circum-radius:
    • \(\frac{r}{R} = \frac{\frac{s \sqrt{3}}{6}}{\frac{s}{\sqrt{3}}} = \frac{1}{2}\)
  2. Ratio of the circum-radius to the ex-radius:
    • \(\frac{R}{r_e} = \frac{\frac{s}{\sqrt{3}}}{\frac{s \sqrt{3}}{2}} = \frac{1}{3}\)

Now, combining these results, the ratio of the in-radius, circum-radius, and one of the ex-radii is:

  • \(r:R:r_e = 1:2:3\)

This matches the given correct answer option: \(1:2:3\).

Therefore, the final answer is:

  • In-radius, circum-radius, and one of the ex-radii of an equilateral triangle are in the ratio: \(1:2:3\).
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