Question:easy

In an electromagnetic wave in vacuum, the relation between peak electric field E_0 and magnetic field B_0 is:

Show Hint

In vacuum always remember: \[ E/B = c \]
Updated On: Jun 10, 2026
  • \(E_0 = B_0\)
  • \(B_0 = cE_0\)
  • \(E_0 = cB_0\)
  • \(E_0 = c^2B_0\)
Show Solution

The Correct Option is C

Solution and Explanation

Step 1: Picture an electromagnetic wave.
An electromagnetic wave has an electric field and a magnetic field. They wiggle at right angles to each other and to the direction the wave travels.

Step 2: Recall the field relation.
At every instant the size of the electric field $E$ and the magnetic field $B$ are linked by the speed of light $c$: \[ E = cB. \]

Step 3: Apply it to the peak values.
The peak, or largest, values follow the same link. So replacing $E$ and $B$ with their peaks gives \[ E_0 = c\,B_0. \]

Step 4: Check the size sense.
Since $c$ is a very large number, the electric field value is much larger than the magnetic field value in usual units, which matches everyday measurements.

Step 5: Rule out the wrong forms.
$E_0 = B_0$ misses the factor $c$. $B_0 = cE_0$ has the roles swapped. $E_0 = c^2 B_0$ uses the wrong power of $c$.

Step 6: State the answer.
The correct relation between the peak fields is the electric peak equals $c$ times the magnetic peak. \[ \boxed{E_0 = cB_0} \]
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