Resistance (R) is calculated as Voltage (V) divided by Current (I), yielding $\frac{V}{I} = \frac{200}{20} = 10 \, \Omega$
The relative change in Resistance ($\frac{\Delta R}{R}$) is the sum of the relative changes in Voltage ($\frac{\Delta V}{V}$) and Current ($\frac{\Delta I}{I}$).
Substituting the values, we get $\frac{\Delta R}{10} = \frac{4}{200} + \frac{0.2}{20}$, which simplifies to $0.02 + 0.01 = 0.03$.
The absolute change in Resistance ($\Delta R$) is therefore $0.3 \, \Omega$.
Consequently, the Resistance (R) is expressed as (10 ± 0.3) Ω.
An infinitely long straight wire carrying current $I$ is bent in a planar shape as shown in the diagram. The radius of the circular part is $r$. The magnetic field at the centre $O$ of the circular loop is :

The heat generated in 1 minute between points A and B in the given circuit, when a battery of 9 V with internal resistance of 1 \(\Omega\) is connected across these points is ______ J. 