Question

In an AC circuit \(E = 50sin(500t)\), \(I = 600sin(500t+\frac{π}{3})mA\). What is the power dissipated in the circuit? [\(cos60^{\circ} = 0.5\)]

• A. \(10\) W
• B. \(75\) W
• C. \(7.5\) W
• D. \(50\) W

Hint:

Use $P=V_{rms}I_{rms}\cos\phi$ with phase $\frac\pi3$.

Answer 1

The Correct Option is C

Step 1: RMS route
$E_{rms}=\frac{50}{\sqrt2}$, $I_{rms}=\frac{0.6}{\sqrt2}$. Product $=15$. Times $\cos60^{\circ}=0.5$ gives $7.5$ W.

Final Answer:
Option (C). \[ \boxed{\text{(C)}} \]