Question:easy

In \(△ABC\) with usual notations, if \(1+tan(\frac{A}{2})tan(\frac{B}{2}) = \frac{k}{s}\) (where \(s\) is the semi-perimeter), then the value of \(k\) is...

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Use tan(A/2)tan(B/2) = (s-c)/s.
Updated On: Oct 1, 2026
  • \(2\)
  • \(a+b-c\)
  • \(a+b\)
  • \(s-c\)
Show Solution

The Correct Option is C

Solution and Explanation

Step 1: Derive it:
Use $\tan\frac A2=\sqrt{\frac{(s-b)(s-c)}{s(s-a)}}$ and $\tan\frac B2=\sqrt{\frac{(s-c)(s-a)}{s(s-b)}}$. Their product is $\sqrt{\frac{(s-c)^2}{s^2}}=\frac{s-c}{s}$.

Step 2: Test with a triangle:
Take an equilateral triangle with $a=b=c=2$. Then $\tan30^\circ\tan30^\circ=\tfrac13$, so the left side is $\tfrac43$. And $s=3$.

Step 3: Find k:
$k=\tfrac43\times3=4=a+b$. Check others: $2\ne4$, $a+b-c=2\ne 4$, $s-c=1\ne4$.

Final Answer:
An equilateral test triangle gives k = 4 = a + b. \[ \boxed{C} \]
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