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List of top Mathematics Questions on Trigonometry asked in MHT CET
If \( \sin x \cos x = \frac{1}{4} \), then the general solution is:
MHT CET - 2026
MHT CET
Mathematics
Trigonometry
In \(\triangle ABC\), if \(\angle C = \frac{2\pi}{3}\), then the value of \(\cos^2 A + \cos^2 B - \cos A \cos B\) is:
MHT CET - 2026
MHT CET
Mathematics
Trigonometry
If $\sin x \cos x = \frac{1}{4}$, then the general solution is:
MHT CET - 2026
MHT CET
Mathematics
Trigonometry
In a $\triangle ABC$, $a = 1$, $b = \sqrt{3}$ and $\angle C = \dfrac{\pi}{6}$. Then the measure of the third side $c =$}
MHT CET - 2026
MHT CET
Mathematics
Trigonometry
If the area of triangle $ABC$ is $b^2 - (c-a)^2$, then $\tan B =$
MHT CET - 2026
MHT CET
Mathematics
Trigonometry
In a triangle $\triangle ABC$, if $a$, $b$, and $c$ are in arithmetic progression, then $\cos A + 2\cos B + \cos C =$
MHT CET - 2026
MHT CET
Mathematics
Trigonometry
If $\sin x \cos x = \frac{1}{4}$, then the general solution is:
MHT CET - 2026
MHT CET
Mathematics
Trigonometry
What is the value of \( \sin^{-1}\left(\frac{1}{2}\right) + \cos^{-1}\left(\frac{1}{2}\right) \)?
MHT CET - 2026
MHT CET
Mathematics
Trigonometry
Find the value of \( \tan(105^\circ) \) using compound angle identities.
MHT CET - 2026
MHT CET
Mathematics
Trigonometry
If \( I(\theta) = \cos \theta_1 \cos \theta_2 \cos \theta_3 \dots \cos \theta_n \), then \[ \tan \theta_1 + \tan \theta_2 + \tan \theta_3 + \cdots + \tan \theta_n = ? \]
MHT CET - 2025
MHT CET
Mathematics
Trigonometry
In a triangle ABC, with usual notations, \[ \tan \left( \frac{A}{4} \right) = \frac{5}{6}, \quad \tan \left( \frac{C}{2} \right) = \frac{2}{5}, \] then
MHT CET - 2025
MHT CET
Mathematics
Trigonometry
With usual notations, the perimeter of a triangle ABC is 6 times the arithmetic mean of sine of its angles. If \( a = 1 \), then \( \angle A = \)
MHT CET - 2025
MHT CET
Mathematics
Trigonometry
The circumradius of a triangle whose sides are 10 units, 8 units and 6 units is ______.
MHT CET - 2025
MHT CET
Mathematics
Trigonometry
With usual notations in $\triangle ABC$, if $\angle B = \pi/2$, and $\tan A, \tan C$ are roots of equation $px^2 + qx + r = 0, p \neq 0$, then ______.
MHT CET - 2025
MHT CET
Mathematics
Trigonometry
In a triangle ABC, with usual notations, if $a = 5$, $b = 7$, $\sin A = \frac{3}{4}$, then total number of triangles possible are ______.
MHT CET - 2025
MHT CET
Mathematics
Trigonometry
In a triangle ABC, with usual notations, $(a + b + c)(a + b - c) = 3ab$, then $\angle C = $ ______.
MHT CET - 2025
MHT CET
Mathematics
Trigonometry
In a triangle ABC, with usual notations, $\cot\left(\frac{A+B}{2}\right) \cdot \tan\left(\frac{A-B}{2}\right) = $ ______.
MHT CET - 2025
MHT CET
Mathematics
Trigonometry
If the angles A, B and C of a triangle are in A.P. and if a, b and c denote the length of the sides opposite to A, B and C respectively, then the value of $\frac{a}{b}sin~2B+\frac{b}{a}sin~2A$ is}
MHT CET - 2025
MHT CET
Mathematics
Trigonometry
In a triangle ABC with usual notations if $\angle A=30^{\circ}$, then the value of $(1+\frac{a}{c}+\frac{b}{c})(1+\frac{c}{b}-\frac{a}{b})=$
MHT CET - 2025
MHT CET
Mathematics
Trigonometry
In a triangle PQR with usual notations, $\angle R=\frac{\pi}{2}$. If $\tan\frac{P}{2}$ and $\tan\frac{Q}{2}$ are the roots of the equation $ax^{2}+bx+c=0(a\ne0),$ then}
MHT CET - 2025
MHT CET
Mathematics
Trigonometry
The value of (\tan [2 \tan^{-1} \frac{1}{5} - \frac{\pi}{4}]) is
MHT CET - 2025
MHT CET
Mathematics
Trigonometry
In a triangle (ABC), with usual notations, the sides (a, b, c) are such that they are roots of the equation (x^3 - 11x^2 + 38x - 40 = 0) then (\frac{\cos A}{a} + \frac{\cos B}{b} + \frac{\cos C}{c} = )
MHT CET - 2025
MHT CET
Mathematics
Trigonometry
The general solutions of the equation (\tan^2 \theta + \sec 2\theta = 1) are
MHT CET - 2025
MHT CET
Mathematics
Trigonometry
With usual notation, in a triangle ABC $\frac{b+c}{11} = \frac{c+a}{12} = \frac{a+b}{13}$, then the value of $\cos B$ is equal to
MHT CET - 2025
MHT CET
Mathematics
Trigonometry
If $( \sin(\alpha + \beta) = 1, \sin(\alpha - \beta) = \frac{1}{2}, \alpha, \beta \in [0, \pi/2] ), then ( \tan(\alpha + 2\beta) \cdot \tan(2\alpha + \beta) = ) $
MHT CET - 2025
MHT CET
Mathematics
Trigonometry
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