Question:medium

In a simple saturated Vapour compression refrigeration cycle, the enthalpy at various state points are: 10 kJ/kg, 45 kJ/kg and 25 kJ/kg. The mass flow rate of refrigerant is 2 kg/s:
  1. The power consumption of compressor is 40 kJ/kg
  2. The refrigeration capacity is 70 kW
  3. The COP is 1.75
  4. Heat rejected in condenser is 110 kW
Choose the correct answer from the options given below.

Show Hint

In refrigeration cycles COP can be calculated as the ratio of refrigeration capacity to the work input
Updated On: Jan 17, 2026
  • (A) and (D) only.
  • (A), (B) and (C) only
  • (A), (B), (C) and (D).
  • (B), (C) and (D) only.
Show Solution

The Correct Option is C

Solution and Explanation

Based on refrigeration cycle relations, the following parameters are derived:

  • Refrigeration capacity \( \dot{Q_L} \) is calculated as \( m \times (h_1 - h_4) \), equating to \( 2 \times (45 - 10) = 70 \, \text{kW}. \)
  • Power consumption \( \dot{W} \) is determined by \( m \times (h_2 - h_1) \), approximately \( 2 \times(h_2 - 45) \approx 40 \, \text{kJ/kg}. \)
  • The Coefficient of Performance (COP) is derived as: \[ \text{COP} = \frac{\text{Refrigeration capacity}}{\text{Power input}} = \frac{70}{40} = 1.75. \]
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