Question

In a set of the given reactions, acetic acid yielded a product C.
CH₃COOH+PCl₅ \(\rightarrow\) A  \(\xrightarrow[Anh.\,AlCl_3]{C_6H_6}\) B  \(\xrightarrow[ether]{C2H5MgBr}\)  ‘C’, product C would be 

• A. CH₃CH(OH)C₂H₅
• B. CH₃COC₆H₅
• C. CH₃CH(OH)C₆H₅
• D.

Answer 1

The Correct Option is D

To determine the product 'C' formed from the given set of reactions, let us analyze each step:

1. Reaction of acetic acid with PCl₅:

   When acetic acid (CH₃COOH) reacts with phosphorus pentachloride (PCl₅), it forms acetyl chloride (CH₃COCl) as the product 'A'. The reaction is as follows:

   CH₃COOH + PCl₅ → CH₃COCl + POCl₃ + HCl

2. Friedel-Crafts acylation with benzene:

   Acetyl chloride (CH₃COCl) undergoes Friedel-Crafts acylation in the presence of anhydrous AlCl₃ as a catalyst and benzene (C₆H₆). This forms acetophenone (CH₃COC₆H₅) as product 'B'. The reaction is as follows:

   CH₃COCl + C₆H₆ → CH₃COC₆H₅ + HCl

3. Reaction with Grignard reagent:

   When acetophenone (CH₃COC₆H₅) reacts with ethylmagnesium bromide (C₂H₅MgBr) in the presence of an etheral solvent, the final product is 2-phenylpropan-2-ol. This occurs through the addition of the Grignard reagent to the carbonyl group, and for acetophenone, this leads to the formation of a tertiary alcohol after hydrolysis. The reaction is as follows:

   CH₃COC₆H₅ + C₂H₅MgBr → (CH₃)₂C(OH)C₆H₅

Based on the steps outlined, the final product 'C' would be 2-phenylpropan-2-ol, which corresponds to the given image in the options.

This confirms that the correct answer is the given structure of 2-phenylpropan-2-ol.