Question:medium

In a series LCR circuit, the voltage across the resistor, capacitor and inductor is \(10\ \text{V}\) each. If the capacitor is short circuited, the voltage across the inductor will be

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If \(V_L=V_C\), the circuit is in resonance and \[ R=X_L. \] After removing the capacitor, treat the circuit as an \(RL\) circuit and use \[ Z=\sqrt{R^2+X_L^2}. \]
  • \(10\ \text{V}\)
  • \(5\sqrt{2}\ \text{V}\)
  • \(\dfrac{5}{\sqrt2}\ \text{V}\)
  • \(10\sqrt2\ \text{V}\)
Show Solution

The Correct Option is D

Solution and Explanation

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