List of top Physics Questions on The Series RLC Circuit asked in CBSE Class XII

An inductor of \(\frac{5}{\pi}\,H\), a capacitor of \(\frac{50}{\pi}\,\mu F\) and a resistor of \(400\,\Omega\) are connected in series across an ac voltage \[ v = 140 \sin(100\pi t)\,V. \] Calculate:
• (I) impedance of the circuit
• (II) rms value of current in the circuit} (Take \(\sqrt{2}=1.4\))
A series combination of \(L\), \(C\) and \(R\) is connected to an a.c. source. Using a phasor diagram, derive an expression for the impedance of the circuit and phase difference between \(V\) and \(I\).
In a series LCR circuit, the voltage across the resistor, capacitor and inductor is \(10\ \text{V}\) each. If the capacitor is short circuited, the voltage across the inductor will be
An ac voltage \(V = 280 \sin (100\pi t)\) volt is connected across a series LCR circuit in which \(R = 400 \, \Omega\), \(L = \frac{5}{\pi} \, \text{H}\) and \(C = \frac{50}{\pi} \, \mu\text{F}\). Taking \(\sqrt{2} = 1.4\), calculate :
(I) impedance of the circuit.
(II) rms value of current that flows in the circuit.
(III) power factor of the circuit.
A series combination of \(L\), \(C\) and \(R\) is connected to an a.c. source. Using a phasor diagram, derive an expression for the impedance of the circuit and phase difference between \(V\) and \(I\).
In a series LCR circuit, the voltage across the resistor, capacitor and inductor is \(10\ \text{V}\) each. If the capacitor is short circuited, the voltage across the inductor will be
An ac voltage \(V = 280 \sin (100\pi t)\) volt is connected across a series LCR circuit in which \(R = 400 \, \Omega\), \(L = \frac{5}{\pi} \, \text{H}\) and \(C = \frac{50}{\pi} \, \mu\text{F}\). Taking \(\sqrt{2} = 1.4\), calculate :
(I) impedance of the circuit.
(II) rms value of current that flows in the circuit.
(III) power factor of the circuit.