Question:medium
In a PNP transistor, \(10^{10}\) holes enter the emitter in \(10^{-6}\,s\). If 2% of holes is lost in the base, then the current amplification factor is
In a PNP transistor, \(10^{10}\) holes enter the emitter in \(10^{-6}\,s\). If 2% of holes is lost in the base, then the current amplification factor is
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\(\beta = \frac{\text{carriers reaching collector}}{\text{lost carriers}}\)
Updated On: May 8, 2026
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The Correct Option is A
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