Given a parallel plate capacitor connected to an AC source, demonstrate that the sum of conduction current \( I_c \) and displacement current \( I_d \) remains constant throughout the circuit.
In AC circuits, the current direction reverses periodically. As charges accumulate and deplete on the capacitor plates, a fluctuating electric field is established between them. This varying electric field generates a displacement current \( I_d \) within the dielectric material.
Maxwell's findings indicate:
\( I_c = I_d \)
This equality ensures that current flow is continuous across the entire circuit, including the dielectric region between the capacitor plates where no physical charge carriers are present.
Yes, Kirchhoff’s first law (junction rule) is applicable to each capacitor plate, as the combined value of conduction current \( I_c \) and displacement current \( I_d \) is invariant at all points in the circuit.
Rationale: The presence of displacement current prevents charge buildup at any circuit point. This maintains current continuity, allowing the junction rule:
\( \sum I_{\text{in}} = \sum I_{\text{out}} \)
to be valid even at the capacitor plate surfaces.
The concept of displacement current resolves the discontinuity in the dielectric region of a capacitor, thus universally validating Kirchhoff’s current law in time-varying (AC) circuits.
The electric field of a plane electromagnetic wave, travelling in an unknown non-magnetic medium is given by,
\[ E_y = 20 \sin (3 \times 10^6 x - 4.5 \times 10^{14} t) \, \text{V/m} \] (where \(x\), \(t\) and other values have S.I. units). The dielectric constant of the medium is ____________.