Question:medium

In a deterministic finite automaton, the behaviour of transitions is strictly defined for every input symbol at each state. Identify the statement that correctly describes this property.

Show Hint

If you are drawing a DFA for an alphabet $\{0, 1\}$, every single state you draw MUST have exactly one arrow leaving it labeled '0' and exactly one arrow labeled '1'.
Updated On: Jul 4, 2026
  • DFA can have $\epsilon$ (epsilon) transitions.
  • DFA can recognize all context-free languages.
  • DFA has exactly one transition for each symbol from every state.
  • DFA can have multiple start states.
Show Solution

The Correct Option is C

Solution and Explanation

Was this answer helpful?
0

Top Questions on Regular expressions and finite automata