Question:medium

Let \( \Sigma = \{1,2,3,4\} \). For \( x \in \Sigma^* \), let \( {prod}(x) \) be the product of symbols in \( x \) modulo 7. We take \( {prod}(\epsilon) = 1 \), where \( \epsilon \) is the null string. For example, \[ {prod}(124) = (1 \times 2 \times 4) \mod 7 = 1. \] Define \[ L = \{ x \in \Sigma^* \mid {prod}(x) = 2 \}. \] The number of states in a minimum state DFA for \( L \) is ___________. (Answer in integer)

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For problems involving modular arithmetic in a DFA, consider the number of possible distinct residue classes as the number of states required.
Updated On: Jan 30, 2026
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Correct Answer: 6

Solution and Explanation

Each string over the alphabet \(\Sigma=\{1,2,3,4\}\) produces a value obtained by multiplying its symbols and reducing the result modulo \(7\). The empty string contributes the value \(1\).

While reading a string from left to right, the only information that matters is the current product modulo \(7\). Appending a symbol multiplies this value by \(1,2,3,\) or \(4\) and reduces it modulo \(7\).

Since all symbols are non-zero modulo \(7\), the value \(0\) is never produced. Starting from \(1\), repeated multiplication by \(\{1,2,3,4\}\) generates all non-zero residues:

\(\{1,2,3,4,5,6\}\)

Each of these values can occur as the product of some string, and from each value the future behavior differs depending on whether the product can be driven to \(2\). Hence, none of these values can be merged without changing the language.

Therefore, the automaton must have one distinct state for each of the six possible non-zero products modulo \(7\).

Hence, the number of states in the minimum DFA is:

\(\boxed{6}\)

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