In a cyclic \(pV\) process forming a square loop from \((p = 1 \text{ atm}, V = 2\text{L})\) to \((p = 3 \text{ atm}, V = 4\text{L})\), then, the net heat absorbed by the gas is:
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Whenever a problem asks for the "net heat absorbed" or "total work done" in a cyclic loop, skip calculating separate step-by-step pathways entirely! Simply find the enclosed area of the shape. Just be careful to double-check the direction: Clockwise = Positive Work, Counter-clockwise = Negative Work.