Question:easy
In a common emitter transistor amplifier, AC current gain is \(65\), the load resistance is \(5400\,\Omega\) and input resistance of the transistor is \(450\,\Omega\). The voltage gain is
In a common emitter transistor amplifier, AC current gain is \(65\), the load resistance is \(5400\,\Omega\) and input resistance of the transistor is \(450\,\Omega\). The voltage gain is
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Voltage gain = current gain times (R_load / R_input).
Updated On: Oct 1, 2026
- \(460\)
- \(540\)
- \(780\)
- \(7800\)
Show Solution
The Correct Option is C
Solution and Explanation
Step 1: Compute the resistance ratio first:
$\frac{5400}{450} = 12$.
Step 2: Multiply by the current gain:
$12\times65 = 12\times60 + 12\times5 = 720 + 60 = 780$.
Step 3: Check:
Voltage gain is much larger than the current gain when $R_L$ exceeds $R_{in}$, as here.
Final Answer:
The voltage gain is 780, option (C). \[ \boxed{780} \]
$\frac{5400}{450} = 12$.
Step 2: Multiply by the current gain:
$12\times65 = 12\times60 + 12\times5 = 720 + 60 = 780$.
Step 3: Check:
Voltage gain is much larger than the current gain when $R_L$ exceeds $R_{in}$, as here.
Final Answer:
The voltage gain is 780, option (C). \[ \boxed{780} \]
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