Question:medium

In a closed hall of volume 5000 m³, the total absorption of the interior surfaces is 200 metric sabin. The reverberation time is:

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Sabine's Formula is the gold standard for calculating how long sound "lingers" in a room.
  • 1 s
  • 2 s
  • 3 s
  • 4 s
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The Correct Option is D

Solution and Explanation

Step 1: Understanding the Concept:
The reverberation time is the time taken for the sound pressure level to decay by 60 dB. This is calculated using Sabine's formula, which relates the volume of the hall and the total absorption.
Step 2: Key Formula or Approach:
Sabine's Formula: \( T = \frac{0.16V}{A} \)
Where: * \( V \) = Volume of the hall (in m³) * \( A \) = Total absorption (in metric sabins)
Step 3: Detailed Explanation:
Given: \( V = 5000 \text{ m}^3 \) and \( A = 200 \text{ sabins} \). Substitute the values into the formula: \[ T = \frac{0.16 \times 5000}{200} \] \[ T = \frac{16 \times 50}{200} \] \[ T = \frac{800}{200} = 4 \text{ s} \]
Step 4: Final Answer:
The reverberation time is 4 s.
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