Question:medium

In a 600 m race, the ratio of the speeds of two participants A and B is 4:5. If A has a head start of 200 m, then the distance by which A wins is:

Updated On: Mar 27, 2026
  • 500 m
  • 200 m
  • 100 m
  • 120 m
Show Solution

The Correct Option is C

Solution and Explanation

This problem requires an initial comprehension of the scenario, followed by a calculation of the result using the provided ratio and head start.
Step 1: Data Comprehension
  • Race distance: 600 m
  • Speed ratio (A:B): 4:5
  • A's head start: 200 m
Step 2: Calculate Effective Distance for A
  • With a 200 m head start, A needs to cover (600 - 200) = 400 m.
Step 3: Calculate Time for Each Participant
  • Assume A's speed = 4x and B's speed = 5x.
  • Time for A to cover 400 m = 400/(4x) = 100/x
  • Time for B to cover 600 m = 600/(5x) = 120/x
Step 4: Determine the Outcome
  • Since 100/x < 120/x, A finishes first.
  • In 100/x time, B covers 5x * (100/x) = 500 m.
  • Therefore, B is at 500 m when A finishes.
  • A wins by a margin of 600 m (total distance for B) - 500 m (distance covered by B) = 100 m.
A wins by 100 m.
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