Question:medium
If \(y = \sec (\tan^{-1} x)\), then \(\frac{dy}{dx}\) at \(x = \sqrt{3}\) is equal to
If \(y = \sec (\tan^{-1} x)\), then \(\frac{dy}{dx}\) at \(x = \sqrt{3}\) is equal to
Show Hint
\(\sec(\tan^{-1} x) = \sqrt{1 + x^2}\) is a useful identity.
Updated On: Apr 24, 2026
- \(\frac{2\sqrt{3}}{3}\)
- \(\frac{1}{2}\)
- 2
- \(\frac{\sqrt{3}}{2}\)
- \(2\sqrt{3}\)
Show Solution
The Correct Option is D
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