Question:medium

If $y = \frac{(a \cos x + b \sin x + c)}{\sin x}$ then $\frac{dy}{dx} = $

Show Hint

Split the fraction! It's much faster than using the Quotient Rule for simple denominators.
  • $-a \csc^{2} x - c \csc x \cot x$
  • $-a \csc^{2} x$
  • $-a \csc^{2} x + b \sec^{2} x + c \csc x \cot x$
  • $a \csc^{2} x - c \csc x \cot x$
Show Solution

The Correct Option is A

Solution and Explanation

Step 1: Understanding the Concept:
To differentiate this function, it is easier to simplify the fraction by dividing each term in the numerator by the denominator before applying differentiation rules.
Step 2: Key Formula or Approach:
1. Simplify: \(y = a \cot x + b + c \csc x\).
2. Derivatives: \(\frac{d}{dx}(\cot x) = -\csc^2 x\) and \(\frac{d}{dx}(\csc x) = -\csc x \cot x\).
Step 3: Detailed Explanation:
Split the terms: \[ y = \frac{a \cos x}{\sin x} + \frac{b \sin x}{\sin x} + \frac{c}{\sin x} \] \[ y = a \cot x + b + c \csc x \] Differentiate with respect to \(x\): \[ \frac{dy}{dx} = a(-\csc^2 x) + 0 + c(-\csc x \cot x) \] \[ \frac{dy}{dx} = -a \csc^2 x - c \csc x \cot x \]
Step 4: Final Answer:
The derivative \( \frac{dy}{dx} \) is \( -a \csc^2 x - c \csc x \cot x \).
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