The system of equations is:
\[\nx + y = 7 \quad \text{and} \quad 3x - 2y = 11\n\]
Solve the first equation for \(y\):
\[\ny = 7 - x\n\]
Substitute into the second equation:
\[\n3x - 2(7 - x) = 11 \quad \Rightarrow \quad 3x - 14 + 2x = 11 \quad \Rightarrow \quad 5x = 25 \quad \Rightarrow \quad x = 5\n\]
Substitute \(x = 5\) into \(x + y = 7\):
\[\n5 + y = 7 \quad \Rightarrow \quad y = 2\n\]
Therefore, the solution is \(x = 5\), \(y = 2\).