Question:medium

If \[ x = \sqrt{e^{\sin^{-1} t}} \quad \text{and} \quad y = \sqrt{e^{\cos^{-1} t}}, \] then find \[ \frac{d^2 y}{dx^2}. \]

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When dealing with parametric equations involving inverse trigonometric functions, try to simplify the product or sum of the variables first using fundamental identities like $\sin^{-1}t + \cos^{-1}t = \frac{\pi}{2}$. This can significantly reduce the complexity of differentiation.
Updated On: Apr 28, 2026
  • \[ -\frac{y}{x^2} \]
  • $\frac{y}{2x^{2}}$

  • $\frac{2y}{x^{2}}$

  • $-\frac{2y}{x^{2}}$ 
     

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The Correct Option is A

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