Question:medium

If \[ y = \frac{x}{x+1} + \frac{x+1}{x}, \] then \[ \frac{d^2 y}{dx^2} \text{ at } x = 1 \text{ is equal to:} \]

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Simplify the function before differentiating to reduce errors.
Updated On: Mar 23, 2026
  • \( \dfrac{7}{4} \)
  • \( \dfrac{7}{8} \)
  • \( \dfrac{1}{4} \)
  • -(7)/(8)
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The Correct Option is D

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