p.B(n, p):P(X = k) = C(n, k) × pk × (1 - p)n-kn = 7 and P(X = 3) = P(X = 5).C(7, 3) × p3 × (1 - p)4 = C(7, 5) × p5 × (1 - p)2C(7, 3) = 35 and C(7, 5) = 21. Let q = 1 - p.35p3q4 = 21p5q27p3q2 (assuming p ≠ 0 and q ≠ 0):5q2 = 3p2q = 1 - p:5(1 - p)2 = 3p25(1 - 2p + p2) = 3p25 - 10p + 5p2 = 3p22p2 - 10p + 5 = 0p using the quadratic formula:p = [10 ± √(100 - 40)] / 4p = [10 ± √60] / 4p = [10 ± 2√15] / 4p = (5 ± √15) / 2p is a probability, 0 ≤ p ≤ 1.√15 ≈ 3.87(5 + 3.87) / 2 > 1 (Rejected)(5 - 3.87) / 2 < 1 (Accepted)p = (5 - √15) / 2.p is (5 - √15) / 2.
If \(S=\{1,2,....,50\}\), two numbers \(\alpha\) and \(\beta\) are selected at random find the probability that product is divisible by 3 :
The probability of hitting the target by a trained sniper is three times the probability of not hitting the target on a stormy day due to high wind speed. The sniper fired two shots on the target on a stormy day when wind speed was very high. Find the probability that
(i) target is hit.
(ii) at least one shot misses the target. 