Question

If $ {\lambda }_v , {\lambda }_x,{\lambda }_m $ represent the wavelengths of visible light, X-rays and microwaves respectively, then

• A. $ {\lambda }_m > {\lambda }_x > {\lambda }_v$
• B. $ {\lambda }_m > {\lambda }_v > {\lambda }_x $
• C. $ {\lambda }_v > {\lambda }_x > {\lambda }_m $
• D. ${\lambda } _v> {\lambda }_m > {\lambda }_ x $

Answer 1

The Correct Option is B

The question requires us to arrange the wavelengths of visible light, X-rays, and microwaves in order of size. Let's discuss the electromagnetic spectrum to reach a conclusion:

1. The electromagnetic spectrum is ordered by frequency and wavelength. In terms of wavelength, it typically follows the order from gamma rays with the smallest wavelength to radio waves with the largest wavelength.
2. Microwaves typically have wavelengths ranging from 1 millimeter to 1 meter. They fall in the range of the spectrum larger than infrared light but smaller than radio waves.
3. Visible light has wavelengths roughly between 400 nm (nanometers) and 700 nm. This falls in between infrared and ultraviolet light on the spectrum.
4. X-rays are much shorter in wavelength, typically ranging from 0.01 to 10 nanometers, and they fall between gamma rays and ultraviolet light on the spectrum.
5. To arrange them in increasing order of wavelength: X-rays have the shortest wavelength, followed by visible light, and microwaves have the longest wavelength.

Therefore, the correct order of wavelengths is:

1. ${\lambda}_x < {\lambda}_v < {\lambda}_m$

Thus, the correct option is: $ {\lambda}_m > {\lambda}_v > {\lambda}_x $.