The given question involves an understanding of genetics, specifically the concept of dominance in blood group inheritance. Let's analyze the scenario described:
An individual with 'AB' blood group genotype has both 'A' and 'B' alleles. In the case of another such individual marrying and having children, the possible genotypes of their children from genetic crosses (Punnett square) can be:
| A | B | |
|---|---|---|
| A | AA | AB |
| B | AB | BB |
From this cross, the genotype distribution of the children is as follows:
The phenotypic ratio obtained is 1 : 2 : 1 of Blood Group 'A' : 'AB' : 'B'.
In this context, 'AB' blood group individuals express both 'A' and 'B' antigens simultaneously. This equal expression of both alleles in the phenotype without one being dominant over the other is known as Codominance. Therefore, seeing both 'A' and 'B' proteins in 'AB' individuals is a classic case of codominance.
Thus, the correct answer is Codominance. Here is a brief explanation of why the other options are not applicable: