If two moles of an ideal gas at 500 K occupies a volume of 41 litres, the pressure of the gas is (R = 0.082 L atm K\textsuperscript{--1} mol\textsuperscript{--1})
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Look for numerical relationships in KEAM questions! Often $R \times T$ will be a multiple of the volume or pressure given. Here, $0.082 \times 500 = 41$ exactly, which simplifies the calculation significantly.