Question:medium
If transistor having \(α = 0.9\), is used in CE configuration, then for a change of \(0.4\) mA in base current, what will be the change in collector current?
If transistor having \(α = 0.9\), is used in CE configuration, then for a change of \(0.4\) mA in base current, what will be the change in collector current?
Show Hint
\(\beta=\frac{\alpha}{1-\alpha}\) and \(\Delta I_C=\beta\Delta I_B\).
Updated On: Oct 1, 2026
- \(3.6\) mA
- \(4\) mA
- \(0.9\) mA
- \(36\) mA
Show Solution
The Correct Option is A
Solution and Explanation
Step 1: Plan:
Use $I_E = I_B + I_C$ and $I_C = \alpha I_E$.
Step 2: Steps:
$I_C = \alpha(I_B + I_C)$, so $I_C(1-\alpha) = \alpha I_B$, i.e. $\Delta I_C = \frac{\alpha}{1-\alpha}\Delta I_B = 9\times0.4 = 3.6$ mA.
Final Answer:
The change in collector current is $3.6$ mA, option (A). \[ \boxed{3.6\ \text{mA}} \]
Use $I_E = I_B + I_C$ and $I_C = \alpha I_E$.
Step 2: Steps:
$I_C = \alpha(I_B + I_C)$, so $I_C(1-\alpha) = \alpha I_B$, i.e. $\Delta I_C = \frac{\alpha}{1-\alpha}\Delta I_B = 9\times0.4 = 3.6$ mA.
Final Answer:
The change in collector current is $3.6$ mA, option (A). \[ \boxed{3.6\ \text{mA}} \]
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