Question

If \(\theta\) is the angle between the circles \[ x^{2}+y^{2}+2x-4y-4=0,\quad x^{2}+y^{2}-4x-6y-3=0 \] then \(\cos\theta=\)

• A. \(\frac{1}{2}\)
• B. \(-\frac{5}{8}\)
• C. \(-\frac{3}{8}\)
• D. \(\frac{\sqrt3}{2}\) \bigskip

Hint:

Angle between circles can be found using center-distance formula directly.

Answer 1

The Correct Option is C