Question:medium

If there is an error of 3% in the volume of a sphere then the percentage error in its radius is

Show Hint

For $y = x^{n}$, the percentage error in $y$ is $n$ times the percentage error in $x$. Since volume is $r^{3}$, the factor is 3.
  • 1%
  • 2%
  • 3%
  • 3/10%
Show Solution

The Correct Option is A

Solution and Explanation

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