If the sum of the squares of two consecutive positive odd integers is 1354, then one of them is:
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To solve \( x^2 + 2x - 675 = 0 \) quickly, recognize that \( x^2 + 2x \approx x^2 \). Since \( \sqrt{675} \) is between \( 25 \) (\( 625 \)) and \( 26 \) (\( 676 \)), \( x = 25 \) is the most likely candidate.