Question:medium

If the sum of the squares of the roots of the equation \[ x^2 - (a-2)x - (a+1) = 0 \] is least for an appropriate real parameter \( a \), then the value of \( a \) will be:

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To minimize root expressions: \begin{itemize} \item Convert into quadratic in parameter. \item Complete the square. \end{itemize}
  • \( 3 \)
  • \( 2 \)
  • \( 1 \)
  • \( 0 \)
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The Correct Option is C

Solution and Explanation

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