Question:medium

Let \[ A = \begin{bmatrix} 5 & 5\alpha & \alpha \\ 0 & \alpha & 5\alpha \\ 0 & 0 & 5 \end{bmatrix} \] If \[ |A|^2 = 25 \] then \( |\alpha| \) equals:

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For triangular matrices: Determinant = product of diagonal entries. Squared determinant questions often reduce to simple algebra.
  • \( 5^2 \)
  • \( 1 \)
  • \( \frac{1}{5} \)
  • \( 5 \)
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The Correct Option is B

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