Question:medium

If the statement $(p \wedge q) \rightarrow (r \vee \neg s)$ is False (F), then the truth values of $p, q, r$ and $s$ are respectively

Show Hint

The key rule for implication is: \[ T \rightarrow F = F \] This is the \textbf{only case} when a conditional statement becomes False. Use this rule first to determine the truth values of compound logical expressions.
Updated On: Apr 15, 2026
  • T, T, F, T
  • T, F, T, F
  • F, F, T, T
  • T, T, T, F
Show Solution

The Correct Option is A

Solution and Explanation

Step 1: Understanding the Question:
The question provides a compound conditional statement that is False and asks for the individual truth values of the component statements.
Step 3: Detailed Explanation:
A conditional statement $X \rightarrow Y$ is False only when the antecedent $X$ is True (T) and the consequent $Y$ is False (F).

Given: $(p \wedge q) \rightarrow (r \vee \neg s) \equiv F$
This implies:
1. $(p \wedge q) \equiv T$
For a conjunction $(\wedge)$ to be True, both component statements must be True.
Therefore, $p \equiv T$ and $q \equiv T$.

2. $(r \vee \neg s) \equiv F$
For a disjunction $(\vee)$ to be False, both component statements must be False.
Therefore, $r \equiv F$ and $\neg s \equiv F$.
Since $\neg s \equiv F$, then $s \equiv T$.

Final truth values: $p = T, q = T, r = F, s = T$.
Step 4: Final Answer:
The truth values are (T, T, F, T).
Was this answer helpful?
1