Question:medium

If the reaction is \( 3^{\text{rd}} \) order, if the concentration of reactant is doubled, then the rate is

Show Hint

For these types of questions, simply raise the factor by which concentration changes to the power of the order. If concentration changes by factor $x$, and order is $n$, new rate changes by factor $x^n$. Here, $2^3 = 8$.
Updated On: Apr 21, 2026
  • Increased twice
  • Increased 8 times
  • Unchanged
  • Decreased 2 times
Show Solution

The Correct Option is B

Solution and Explanation

Was this answer helpful?
0