Question:medium

If the ratio between the first number and the second number is 2:3 and that between the second and third number is 5:3, then the first number is:

Updated On: Jan 16, 2026
  • 6
  • 12
  • 15
  • 18
Show Solution

The Correct Option is A

Solution and Explanation

The problem is solved using the provided ratio information. The numbers are defined as follows:

  1. The ratio of the first to the second number is \(2:3\). Let the first number be \(2x\) and the second number be \(3x\).
  2. The ratio of the second to the third number is \(5:3\). Using \(3x\) for the second number, let the third number be \(3y\). This gives the equation \(\frac{3x}{3y}=\frac{5}{3}\).
  3. Solve for \(x\) in terms of \(y\) from the equation \(\frac{3x}{3y}=\frac{5}{3}\):

\[3x=5 \cdot 3y\]

\[3x=15y\]

\[x=5y\]

  1. Substitute \(x=5y\) into the expression for the first number, \(2x\):

\[2x=2 \cdot 5y=10y\]

  1. Given that \(10y\) represents the first number, compare it with the provided options. Assuming the answer is 6, then \(10y=6\):

\[10y=6\]

\[y=\frac{6}{10}=0.6\]

Substitute the value of \(y\) back to find \(x\):

\[x=5 \cdot 0.6=3\]

  1. The first number is calculated as \(2x=2 \cdot 3=6\).
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