If the rate of change of electric field across the plates of a parallel plate capacitor is E and the displacement current is I, then the area of one plate of the capacitor is (\(\epsilon_0\) is permittivity of free space)
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The notation in this problem is a bit confusing. "Rate of change of electric field is E" should be interpreted as \(dE/dt\). The displacement current \(I_d = \epsilon_0 d\Phi_E/dt\) is Maxwell's crucial addition to Ampere's law, showing that a changing electric field creates a magnetic field, just like a real current does.