Question

If the potential energy of an electron in an orbit of hydrogen atom is $-6.80$ eV, then the energy required to ionize the atom is

• A. 6.80 eV
• B. 13.6 eV
• C. 3.40 eV
• D. 10.2 eV

Hint:

Remember: $TE = -13.6/n^2$. $PE = -27.2/n^2$. $KE = 13.6/n^2$. Here $PE = -6.8 \Rightarrow n=2$.

Answer 1

The Correct Option is C