Question:medium

If the potential energy of an electron in an orbit of hydrogen atom is $-6.80$ eV, then the energy required to ionize the atom is

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Remember: $TE = -13.6/n^2$. $PE = -27.2/n^2$. $KE = 13.6/n^2$. Here $PE = -6.8 \Rightarrow n=2$.

Updated On: Mar 31, 2026

6.80 eV
13.6 eV
3.40 eV
10.2 eV

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The Correct Option is C

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