Question:medium

If the point P($x_1, y_1$) lying on the curve $y = x^2-x+1$ is the closest point to the line $y = x-3$ then the perpendicular distance from P to the line $3x+4y-2=0$ is

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To find the shortest distance between a curve and a line, find the point on the curve where the tangent is parallel to the line. The shortest distance is then the perpendicular distance from this point to the line.

Updated On: Mar 30, 2026

$16/5$
4
1
$7/5$

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The Correct Option is C

Solution and Explanation

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If the point P($x_1, y_1$) lying on the curve $y = x^2-x+1$ is the closest point to the line $y = x-3$ then the perpendicular distance from P to the line $3x+4y-2=0$ is

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The Correct Option is C

Solution and Explanation

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