If the plane $-4x-2y+2z+\alpha=0$ is at a distance of two units from the plane $2x+y-z+1=0$, then the product of all the possible values of $\alpha$ is
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Before applying the distance formula for parallel planes, make sure to rewrite the equations so that the coefficients of $x, y,$ and $z$ are exactly the same. This ensures you are using the correct values for $D_1$ and $D_2$.