Question:medium
If the one end of a diameter of the circle $x^2 + y^2 + 3x + y - 6 = 0$ is at $(-4,-2)$, then the other end of the diameter is at
If the one end of a diameter of the circle $x^2 + y^2 + 3x + y - 6 = 0$ is at $(-4,-2)$, then the other end of the diameter is at
Show Hint
Centre of circle = midpoint of diameter endpoints.
Updated On: Apr 24, 2026
- $(4,-2)$
- $(1,-1)$
- $(1,1)$
- $(-1,-1)$
- $(1,-2)$
Show Solution
The Correct Option is C
Solution and Explanation
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