Question:medium

If the mean life of a radioactive substance is \[ \frac{20}{\ln4} \] minutes, then the ratio of the number of atoms remaining undecayed and the number of atoms decayed of the substance at a time of \(30\) minutes is

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For radioactive decay, \[ \boxed{ N=N_0e^{-\lambda t}, \qquad \lambda=\frac1{\tau}, } \] where \[ \boxed{\tau} \] is the mean life.
Updated On: Jul 18, 2026
  • \(3:8\)
  • \(7:8\)
  • \(1:7\)
  • \(1:8\)
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The Correct Option is C

Solution and Explanation

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