Question:medium

If the masses of proton and neutron are \(m_{p}\) and \(m_{n}\) respectively, the experimental masses of \({}_{2}He^{4}\) and \({}_{8}O^{16}\) nuclei are \(M_{1}\) and \(M_{2}\) respectively, then

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For every stable nucleus, \[ \text{Actual nuclear mass} < \text{Sum of masses of free nucleons} \] because part of the mass appears as nuclear binding energy.
Updated On: Jun 22, 2026
  • \(M_{2}=8(m_{p}+m_{n})\)
  • \(M_{2}<8(m_{p}+m_{n})\)
  • \(M_{1}=2(m_{p}+m_{n})\)
  • \(M_{1}>2(m_{p}+m_{n})\) \bigskip
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The Correct Option is B

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