Question:medium

If the latus rectum of the ellipse \[ \frac{x^2}{16}+\frac{y^2}{b^2}=1 \] subtends an angle \[ \frac{\pi}{3} \] at the centre of the ellipse, then \(b^2=\)

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For an ellipse \[ \frac{x^2}{a^2}+\frac{y^2}{b^2}=1, \] the endpoints of the latus rectum are \[ \boxed{\left(ae,\pm\frac{b^2}{a}\right)}. \] Use the angle made by the position vectors from the centre.
Updated On: Jul 18, 2026
  • \(9\)
  • \(\dfrac94(\sqrt{13}-1)\)
  • \(\dfrac83(\sqrt{13}-1)\)
  • \(7\)
Show Solution

The Correct Option is C

Solution and Explanation

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