Question:medium

If the intensity of the central maximum in the Young's double slit experiment is $I_0$, what will be the intensity at the same region when one of the slits is blocked by an opaque object?

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Remember the golden rule of interference: Amplitudes add up linearly, but Intensities scale quadratically! Cutting the source sources in half drops the amplitude by $2$, which drops the corresponding intensity by $2^2 = 4$. Thus, the intensity becomes exactly $\frac{I_0}{4}$.
Updated On: May 16, 2026
  • $I_0$
  • $\frac{I_0}{2}$
  • $\frac{I_0}{4}$
  • $\frac{I_0}{8}$
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The Correct Option is C

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