To determine the percentage change in range when the height of a tower used for LOS (Line of Sight) communication is increased, we need to use the formula for the range of LOS communication:
\(d = \sqrt{2Rh}\)
where:
When the height \(h\) is increased by 21%, the new height \(h'\) will be:
\(h' = 1.21h\)
The initial range \(d_1\) is given by:
\(d_1 = \sqrt{2Rh}\)
The new range \(d_2\) with the increased height will be:
\(d_2 = \sqrt{2R \cdot 1.21h} = \sqrt{1.21} \cdot \sqrt{2Rh}\)
Therefore, the new range \(d_2\) is:
\(d_2 = \sqrt{1.21} \cdot d_1\)
Since \(\sqrt{1.21} \approx 1.1\), this means the range also increases by approximately 10%.
Therefore, the percentage change in range is 10%. This matches the correct option.
Match List-I with List-II:
| List-I (Modulation Schemes) | List-II (Wave Expressions) |
|---|---|
| (A) Amplitude Modulation | (I) \( x(t) = A\cos(\omega_c t + k m(t)) \) |
| (B) Phase Modulation | (II) \( x(t) = A\cos(\omega_c t + k \int m(t)dt) \) |
| (C) Frequency Modulation | (III) \( x(t) = A + m(t)\cos(\omega_c t) \) |
| (D) DSB-SC Modulation | (IV) \( x(t) = m(t)\cos(\omega_c t) \) |
Choose the correct answer: